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3113111024213 is a prime number
BaseRepresentation
bin101101010011010011111…
…000000111001001010101
3102000121111001121122202012
4231103103320013021111
5402001122410233323
610342050553154005
7440625536046011
oct55232370071125
912017431548665
103113111024213
11aa0299018383
124234126bb905
13197746714928
14aa965343541
1555ea4a11678
hex2d4d3e07255

3113111024213 has 2 divisors, whose sum is σ = 3113111024214. Its totient is φ = 3113111024212.

The previous prime is 3113111024183. The next prime is 3113111024227. The reversal of 3113111024213 is 3124201113113.

3113111024213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3112973267044 + 137757169 = 1764362^2 + 11737^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113111024213 - 216 = 3113110958677 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3113111024713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556555512106 + 1556555512107.

It is an arithmetic number, because the mean of its divisors is an integer number (1556555512107).

Almost surely, 23113111024213 is an apocalyptic number.

It is an amenable number.

3113111024213 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113111024213 is an equidigital number, since it uses as much as digits as its factorization.

3113111024213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 3113111024213 its reverse (3124201113113), we get a palindrome (6237312137326).

The spelling of 3113111024213 in words is "three trillion, one hundred thirteen billion, one hundred eleven million, twenty-four thousand, two hundred thirteen".