311311130201 has 2 divisors, whose sum is σ = 311311130202. Its totient is φ = 311311130200.

The previous prime is 311311130197. The next prime is 311311130203. The reversal of 311311130201 is 102031113113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 304318825801 + 6992304400 = 551651^2 + 83620^2 .

It is a cyclic number.

It is not a de Polignac number, because 311311130201 - 2² = 311311130197 is a prime.

Together with 311311130203, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 311311130201.

It is not a weakly prime, because it can be changed into another prime (311311130203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155655565100 + 155655565101.

It is an arithmetic number, because the mean of its divisors is an integer number (155655565101).

Almost surely, 2^311311130201 is an apocalyptic number.

It is an amenable number.

311311130201 is a deficient number, since it is larger than the sum of its proper divisors (1).

311311130201 is an equidigital number, since it uses as much as digits as its factorization.

311311130201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 311311130201 its reverse (102031113113), we get a palindrome (413342243314).

The spelling of 311311130201 in words is "three hundred eleven billion, three hundred eleven million, one hundred thirty thousand, two hundred one".