Base | Representation |
---|---|
bin | 100011011001000101100101… |
… | …0110100001111101011010001 |
3 | 1111211021001200100011020212021 |
4 | 1012302023022310033223101 |
5 | 311301010340343221001 |
6 | 3022034222352331441 |
7 | 122400331204243552 |
oct | 10662131264175321 |
9 | 1454231610136767 |
10 | 311311222242001 |
11 | 902143910a81a3 |
12 | 2aaba24a543b81 |
13 | 104926a3626147 |
14 | 56c3787712329 |
15 | 25ecdbca15ba1 |
hex | 11b22cad0fad1 |
311311222242001 has 2 divisors, whose sum is σ = 311311222242002. Its totient is φ = 311311222242000.
The previous prime is 311311222241977. The next prime is 311311222242079. The reversal of 311311222242001 is 100242222113113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 160228381678225 + 151082840563776 = 12658135^2 + 12291576^2 .
It is a cyclic number.
It is not a de Polignac number, because 311311222242001 - 29 = 311311222241489 is a prime.
It is not a weakly prime, because it can be changed into another prime (311311222243001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155655611121000 + 155655611121001.
It is an arithmetic number, because the mean of its divisors is an integer number (155655611121001).
Almost surely, 2311311222242001 is an apocalyptic number.
It is an amenable number.
311311222242001 is a deficient number, since it is larger than the sum of its proper divisors (1).
311311222242001 is an equidigital number, since it uses as much as digits as its factorization.
311311222242001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 311311222242001 its reverse (100242222113113), we get a palindrome (411553444355114).
The spelling of 311311222242001 in words is "three hundred eleven trillion, three hundred eleven billion, two hundred twenty-two million, two hundred forty-two thousand, one".
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