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3113120542544 = 24194570033909
BaseRepresentation
bin101101010011010100011…
…100011010111101010000
3102000121111201112020102222
4231103110130122331100
5402001132324330134
610342051533200212
7440626013001155
oct55232434327520
912017451466388
103113120542544
11aa02a3429671
12423415930068
1319774869818c
14aa96670022c
1555ea5791a2e
hex2d4d471af50

3113120542544 has 10 divisors (see below), whose sum is σ = 6031671051210. Its totient is φ = 1556560271264.

The previous prime is 3113120542513. The next prime is 3113120542559. The reversal of 3113120542544 is 4452450213113.

3113120542544 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 1935270499600 + 1177850042944 = 1391140^2 + 1085288^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97285016939 + ... + 97285016970.

It is an arithmetic number, because the mean of its divisors is an integer number (603167105121).

Almost surely, 23113120542544 is an apocalyptic number.

It is an amenable number.

3113120542544 is a deficient number, since it is larger than the sum of its proper divisors (2918550508666).

3113120542544 is a wasteful number, since it uses less digits than its factorization.

3113120542544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194570033917 (or 194570033911 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 3113120542544 its reverse (4452450213113), we get a palindrome (7565570755657).

The spelling of 3113120542544 in words is "three trillion, one hundred thirteen billion, one hundred twenty million, five hundred forty-two thousand, five hundred forty-four".

Divisors: 1 2 4 8 16 194570033909 389140067818 778280135636 1556560271272 3113120542544