Base | Representation |
---|---|
bin | 100011011001000110001001… |
… | …0011101011001101001001011 |
3 | 1111211021011210002212201012011 |
4 | 1012302030102131121221023 |
5 | 311301020321044304232 |
6 | 3022034541531000351 |
7 | 122400403040651434 |
oct | 10662142235315113 |
9 | 1454234702781164 |
10 | 311312424213067 |
11 | 9021494862a912 |
12 | 2aaba524b990b7 |
13 | 1049283565a824 |
14 | 56c385d1d648b |
15 | 25ece3d2e0547 |
hex | 11b2312759a4b |
311312424213067 has 2 divisors, whose sum is σ = 311312424213068. Its totient is φ = 311312424213066.
The previous prime is 311312424212917. The next prime is 311312424213143. The reversal of 311312424213067 is 760312424213113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311312424213067 - 239 = 310762668399179 is a prime.
It is not a weakly prime, because it can be changed into another prime (311312424214067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155656212106533 + 155656212106534.
It is an arithmetic number, because the mean of its divisors is an integer number (155656212106534).
Almost surely, 2311312424213067 is an apocalyptic number.
311312424213067 is a deficient number, since it is larger than the sum of its proper divisors (1).
311312424213067 is an equidigital number, since it uses as much as digits as its factorization.
311312424213067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 40.
The spelling of 311312424213067 in words is "three hundred eleven trillion, three hundred twelve billion, four hundred twenty-four million, two hundred thirteen thousand, sixty-seven".
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