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311312424213143 is a prime number
BaseRepresentation
bin100011011001000110001001…
…0011101011001101010010111
31111211021011210002212201021222
41012302030102131121222113
5311301020321044310033
63022034541531000555
7122400403040651603
oct10662142235315227
91454234702781258
10311312424213143
119021494862a981
122aaba524b9915b
131049283565a882
1456c385d1d6503
1525ece3d2e0598
hex11b2312759a97

311312424213143 has 2 divisors, whose sum is σ = 311312424213144. Its totient is φ = 311312424213142.

The previous prime is 311312424213067. The next prime is 311312424213151. The reversal of 311312424213143 is 341312424213113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 311312424213143 - 214 = 311312424196759 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (341312424213143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155656212106571 + 155656212106572.

It is an arithmetic number, because the mean of its divisors is an integer number (155656212106572).

Almost surely, 2311312424213143 is an apocalyptic number.

311312424213143 is a deficient number, since it is larger than the sum of its proper divisors (1).

311312424213143 is an equidigital number, since it uses as much as digits as its factorization.

311312424213143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41472, while the sum is 35.

Adding to 311312424213143 its reverse (341312424213113), we get a palindrome (652624848426256).

The spelling of 311312424213143 in words is "three hundred eleven trillion, three hundred twelve billion, four hundred twenty-four million, two hundred thirteen thousand, one hundred forty-three".