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31131244031 is a prime number
BaseRepresentation
bin11100111111100100…
…010001010111111111
32222100120221001110012
4130333210101113333
51002224044302111
622145042333435
72151314131256
oct347744212777
988316831405
1031131244031
1112225859458
12604995a27b
132c21865074
14171479b79d
15c230d248b
hex73f9115ff

31131244031 has 2 divisors, whose sum is σ = 31131244032. Its totient is φ = 31131244030.

The previous prime is 31131244021. The next prime is 31131244057. The reversal of 31131244031 is 13044213113.

It is a weak prime.

It is an emirp because it is prime and its reverse (13044213113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31131244031 - 218 = 31130981887 is a prime.

It is a super-2 number, since 2×311312440312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31131243988 and 31131244006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31131244021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565622015 + 15565622016.

It is an arithmetic number, because the mean of its divisors is an integer number (15565622016).

Almost surely, 231131244031 is an apocalyptic number.

31131244031 is a deficient number, since it is larger than the sum of its proper divisors (1).

31131244031 is an equidigital number, since it uses as much as digits as its factorization.

31131244031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 31131244031 its reverse (13044213113), we get a palindrome (44175457144).

The spelling of 31131244031 in words is "thirty-one billion, one hundred thirty-one million, two hundred forty-four thousand, thirty-one".