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311313031001233 is a prime number
BaseRepresentation
bin100011011001000110011011…
…0101000000111010010010001
31111211021020100101122202001221
41012302030312220013102101
5311301023041414014413
63022035122044325041
7122400424056402232
oct10662146650072221
91454236311582057
10311313031001233
119021512a0a4838
122aaba674243781
1310492901292091
1456c38b9a29089
1525ece766ee68d
hex11b2336a07491

311313031001233 has 2 divisors, whose sum is σ = 311313031001234. Its totient is φ = 311313031001232.

The previous prime is 311313031001173. The next prime is 311313031001249. The reversal of 311313031001233 is 332100130313113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 307359523115584 + 3953507885649 = 17531672^2 + 1988343^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311313031001233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311313031001198 and 311313031001207.

It is not a weakly prime, because it can be changed into another prime (311313035001233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155656515500616 + 155656515500617.

It is an arithmetic number, because the mean of its divisors is an integer number (155656515500617).

Almost surely, 2311313031001233 is an apocalyptic number.

It is an amenable number.

311313031001233 is a deficient number, since it is larger than the sum of its proper divisors (1).

311313031001233 is an equidigital number, since it uses as much as digits as its factorization.

311313031001233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 311313031001233 its reverse (332100130313113), we get a palindrome (643413161314346).

The spelling of 311313031001233 in words is "three hundred eleven trillion, three hundred thirteen billion, thirty-one million, one thousand, two hundred thirty-three".