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311313112402051 is a prime number
BaseRepresentation
bin100011011001000110011101…
…1011110101000100010000011
31111211021020120001211100000001
41012302030323132220202003
5311301023223233331201
63022035134113140431
7122400426065321344
oct10662147336504203
91454236501740001
10311313112402051
1190215171042441
122aaba69755a717
13104929150c2c46
1456c38c67780cb
1525ece7d92d301
hex11b233b7a8883

311313112402051 has 2 divisors, whose sum is σ = 311313112402052. Its totient is φ = 311313112402050.

The previous prime is 311313112402021. The next prime is 311313112402057. The reversal of 311313112402051 is 150204211313113.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (150204211313113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311313112402051 - 221 = 311313110304899 is a prime.

It is not a weakly prime, because it can be changed into another prime (311313112402057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155656556201025 + 155656556201026.

It is an arithmetic number, because the mean of its divisors is an integer number (155656556201026).

Almost surely, 2311313112402051 is an apocalyptic number.

311313112402051 is a deficient number, since it is larger than the sum of its proper divisors (1).

311313112402051 is an equidigital number, since it uses as much as digits as its factorization.

311313112402051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 311313112402051 its reverse (150204211313113), we get a palindrome (461517323715164).

The spelling of 311313112402051 in words is "three hundred eleven trillion, three hundred thirteen billion, one hundred twelve million, four hundred two thousand, fifty-one".