Base | Representation |
---|---|
bin | 1001000011110111011… |
… | …10000000000101010001 |
3 | 1002202112221220022022102 |
4 | 10201323232000011101 |
5 | 20100032201124331 |
6 | 355003152250145 |
7 | 31330430255543 |
oct | 4417356000521 |
9 | 1082487808272 |
10 | 311313301841 |
11 | 110033274433 |
12 | 50402240955 |
13 | 23483930759 |
14 | 110d3889693 |
15 | 81709d84cb |
hex | 487bb80151 |
311313301841 has 2 divisors, whose sum is σ = 311313301842. Its totient is φ = 311313301840.
The previous prime is 311313301757. The next prime is 311313301843. The reversal of 311313301841 is 148103313113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 171976090000 + 139337211841 = 414700^2 + 373279^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311313301841 is a prime.
Together with 311313301843, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (311313301843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155656650920 + 155656650921.
It is an arithmetic number, because the mean of its divisors is an integer number (155656650921).
Almost surely, 2311313301841 is an apocalyptic number.
It is an amenable number.
311313301841 is a deficient number, since it is larger than the sum of its proper divisors (1).
311313301841 is an equidigital number, since it uses as much as digits as its factorization.
311313301841 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 311313301841 its reverse (148103313113), we get a palindrome (459416614954).
The spelling of 311313301841 in words is "three hundred eleven billion, three hundred thirteen million, three hundred one thousand, eight hundred forty-one".
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