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31131343330342 = 229536747298799
BaseRepresentation
bin1110001010000010101001…
…01010010001110000100110
311002020010102211202200101121
413011001110222101300212
513040023442343032332
6150113313001044154
76362110465131463
oct705012452216046
9132203384680347
1031131343330342
119a12801799042
1235a9567a8665a
13144a8999a8c28
14798a9d45c66a
1538ebe72a2797
hex1c5054a91c26

31131343330342 has 8 divisors (see below), whose sum is σ = 48307256892000. Its totient is φ = 15028924366344.

The previous prime is 31131343330319. The next prime is 31131343330369. The reversal of 31131343330342 is 24303334313113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 31131343330298 and 31131343330307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268373649342 + ... + 268373649457.

It is an arithmetic number, because the mean of its divisors is an integer number (6038407111500).

Almost surely, 231131343330342 is an apocalyptic number.

31131343330342 is a deficient number, since it is larger than the sum of its proper divisors (17175913561658).

31131343330342 is a wasteful number, since it uses less digits than its factorization.

31131343330342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 536747298830.

The product of its (nonzero) digits is 69984, while the sum is 34.

Adding to 31131343330342 its reverse (24303334313113), we get a palindrome (55434677643455).

The spelling of 31131343330342 in words is "thirty-one trillion, one hundred thirty-one billion, three hundred forty-three million, three hundred thirty thousand, three hundred forty-two".

Divisors: 1 2 29 58 536747298799 1073494597598 15565671665171 31131343330342