Base | Representation |
---|---|
bin | 1110001010000010101001… |
… | …01010010001110000100110 |
3 | 11002020010102211202200101121 |
4 | 13011001110222101300212 |
5 | 13040023442343032332 |
6 | 150113313001044154 |
7 | 6362110465131463 |
oct | 705012452216046 |
9 | 132203384680347 |
10 | 31131343330342 |
11 | 9a12801799042 |
12 | 35a9567a8665a |
13 | 144a8999a8c28 |
14 | 798a9d45c66a |
15 | 38ebe72a2797 |
hex | 1c5054a91c26 |
31131343330342 has 8 divisors (see below), whose sum is σ = 48307256892000. Its totient is φ = 15028924366344.
The previous prime is 31131343330319. The next prime is 31131343330369. The reversal of 31131343330342 is 24303334313113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 31131343330298 and 31131343330307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268373649342 + ... + 268373649457.
It is an arithmetic number, because the mean of its divisors is an integer number (6038407111500).
Almost surely, 231131343330342 is an apocalyptic number.
31131343330342 is a deficient number, since it is larger than the sum of its proper divisors (17175913561658).
31131343330342 is a wasteful number, since it uses less digits than its factorization.
31131343330342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 536747298830.
The product of its (nonzero) digits is 69984, while the sum is 34.
Adding to 31131343330342 its reverse (24303334313113), we get a palindrome (55434677643455).
The spelling of 31131343330342 in words is "thirty-one trillion, one hundred thirty-one billion, three hundred forty-three million, three hundred thirty thousand, three hundred forty-two".
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