Base | Representation |
---|---|
bin | 1110001010000010110011… |
… | …11110001011001010110001 |
3 | 11002020010200001102112022022 |
4 | 13011001121332023022301 |
5 | 13040024133200313210 |
6 | 150113325502521225 |
7 | 6362112626364122 |
oct | 705013176131261 |
9 | 132203601375268 |
10 | 31131432432305 |
11 | 9a12848016727 |
12 | 35a9591896215 |
13 | 144a8b22a519a |
14 | 798aab214049 |
15 | 38ec00003155 |
hex | 1c5059f8b2b1 |
31131432432305 has 32 divisors (see below), whose sum is σ = 39812423270400. Its totient is φ = 23314839604672.
The previous prime is 31131432432301. The next prime is 31131432432557. The reversal of 31131432432305 is 50323423413113.
It is not a de Polignac number, because 31131432432305 - 22 = 31131432432301 is a prime.
It is a super-2 number, since 2×311314324323052 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31131432432301) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 380357576 + ... + 380439414.
It is an arithmetic number, because the mean of its divisors is an integer number (1244138227200).
Almost surely, 231131432432305 is an apocalyptic number.
It is an amenable number.
31131432432305 is a deficient number, since it is larger than the sum of its proper divisors (8680990838095).
31131432432305 is a wasteful number, since it uses less digits than its factorization.
31131432432305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152293.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 31131432432305 its reverse (50323423413113), we get a palindrome (81454855845418).
The spelling of 31131432432305 in words is "thirty-one trillion, one hundred thirty-one billion, four hundred thirty-two million, four hundred thirty-two thousand, three hundred five".
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