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31131432432557 is a prime number
BaseRepresentation
bin1110001010000010110011…
…11110001011001110101101
311002020010200001102112122122
413011001121332023032231
513040024133200320212
6150113325502522325
76362112626364632
oct705013176131655
9132203601375578
1031131432432557
119a12848016936
1235a95918963a5
13144a8b22a5332
14798aab214189
1538ec00003272
hex1c5059f8b3ad

31131432432557 has 2 divisors, whose sum is σ = 31131432432558. Its totient is φ = 31131432432556.

The previous prime is 31131432432301. The next prime is 31131432432601. The reversal of 31131432432557 is 75523423413113.

It is an a-pointer prime, because the next prime (31131432432601) can be obtained adding 31131432432557 to its sum of digits (44).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30541660655401 + 589771777156 = 5526451^2 + 767966^2 .

It is a cyclic number.

It is not a de Polignac number, because 31131432432557 - 28 = 31131432432301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31131432435557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565716216278 + 15565716216279.

It is an arithmetic number, because the mean of its divisors is an integer number (15565716216279).

Almost surely, 231131432432557 is an apocalyptic number.

It is an amenable number.

31131432432557 is a deficient number, since it is larger than the sum of its proper divisors (1).

31131432432557 is an equidigital number, since it uses as much as digits as its factorization.

31131432432557 is an evil number, because the sum of its binary digits is even.

The product of its digits is 907200, while the sum is 44.

The spelling of 31131432432557 in words is "thirty-one trillion, one hundred thirty-one billion, four hundred thirty-two million, four hundred thirty-two thousand, five hundred fifty-seven".