Base | Representation |
---|---|
bin | 1001000011111000010… |
… | …11010111110010101101 |
3 | 1002202120111101110202101 |
4 | 10201330023113302231 |
5 | 20100041134014013 |
6 | 355004025255101 |
7 | 31330552563502 |
oct | 4417413276255 |
9 | 1082514343671 |
10 | 311321001133 |
11 | 110037652a8a |
12 | 50404934491 |
13 | 234853c804c |
14 | 110d48d14a9 |
15 | 81715098dd |
hex | 487c2d7cad |
311321001133 has 2 divisors, whose sum is σ = 311321001134. Its totient is φ = 311321001132.
The previous prime is 311321001119. The next prime is 311321001151. The reversal of 311321001133 is 331100123113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 292277553129 + 19043448004 = 540627^2 + 137998^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311321001133 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 311321001133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311321001113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155660500566 + 155660500567.
It is an arithmetic number, because the mean of its divisors is an integer number (155660500567).
Almost surely, 2311321001133 is an apocalyptic number.
It is an amenable number.
311321001133 is a deficient number, since it is larger than the sum of its proper divisors (1).
311321001133 is an equidigital number, since it uses as much as digits as its factorization.
311321001133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 311321001133 its reverse (331100123113), we get a palindrome (642421124246).
The spelling of 311321001133 in words is "three hundred eleven billion, three hundred twenty-one million, one thousand, one hundred thirty-three".
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