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3113212102081 is a prime number
BaseRepresentation
bin101101010011011001111…
…001101100010111000001
3102000121202002210221111221
4231103121321230113001
5402001324244231311
610342105003435041
7440631204150454
oct55233171542701
912017662727457
103113212102081
11aa0340085704
12423440525a81
13197761644c13
14aa97493549b
1555ead82a671
hex2d4d9e6c5c1

3113212102081 has 2 divisors, whose sum is σ = 3113212102082. Its totient is φ = 3113212102080.

The previous prime is 3113212102073. The next prime is 3113212102093. The reversal of 3113212102081 is 1802012123113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2320549522225 + 792662579856 = 1523335^2 + 890316^2 .

It is an emirp because it is prime and its reverse (1802012123113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3113212102081 - 23 = 3113212102073 is a prime.

It is a super-2 number, since 2×31132121020812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3113212102181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556606051040 + 1556606051041.

It is an arithmetic number, because the mean of its divisors is an integer number (1556606051041).

Almost surely, 23113212102081 is an apocalyptic number.

It is an amenable number.

3113212102081 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113212102081 is an equidigital number, since it uses as much as digits as its factorization.

3113212102081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 3113212102081 its reverse (1802012123113), we get a palindrome (4915224225194).

The spelling of 3113212102081 in words is "three trillion, one hundred thirteen billion, two hundred twelve million, one hundred two thousand, eighty-one".