Base | Representation |
---|---|
bin | 1001000011111000011… |
… | …00001011000101010001 |
3 | 1002202120111210010221021 |
4 | 10201330030023011101 |
5 | 20100041212224332 |
6 | 355004033555441 |
7 | 31330554430132 |
oct | 4417414130521 |
9 | 1082514703837 |
10 | 311321211217 |
11 | 110037786905 |
12 | 50404a15b81 |
13 | 2348546c863 |
14 | 110d4947c89 |
15 | 817154bc97 |
hex | 487c30b151 |
311321211217 has 2 divisors, whose sum is σ = 311321211218. Its totient is φ = 311321211216.
The previous prime is 311321211211. The next prime is 311321211263. The reversal of 311321211217 is 712112123113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 309181593681 + 2139617536 = 556041^2 + 46256^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311321211217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311321211191 and 311321211200.
It is not a weakly prime, because it can be changed into another prime (311321211211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155660605608 + 155660605609.
It is an arithmetic number, because the mean of its divisors is an integer number (155660605609).
Almost surely, 2311321211217 is an apocalyptic number.
It is an amenable number.
311321211217 is a deficient number, since it is larger than the sum of its proper divisors (1).
311321211217 is an equidigital number, since it uses as much as digits as its factorization.
311321211217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 504, while the sum is 25.
The spelling of 311321211217 in words is "three hundred eleven billion, three hundred twenty-one million, two hundred eleven thousand, two hundred seventeen".
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