Base | Representation |
---|---|
bin | 101101010011011010111… |
… | …110000000101011011111 |
3 | 102000121210100111211002001 |
4 | 231103122332000223133 |
5 | 402001343340323403 |
6 | 10342110443343131 |
7 | 440631512320402 |
oct | 55233276005337 |
9 | 12017710454061 |
10 | 3113230011103 |
11 | aa034a1a7a53 |
12 | 423446521aa7 |
13 | 197765275684 |
14 | aa977077d39 |
15 | 55eb01b6c1d |
hex | 2d4daf80adf |
3113230011103 has 2 divisors, whose sum is σ = 3113230011104. Its totient is φ = 3113230011102.
The previous prime is 3113230011049. The next prime is 3113230011107. The reversal of 3113230011103 is 3011100323113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3113230011103 is a prime.
It is a super-2 number, since 2×31132300111032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3113230011107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556615005551 + 1556615005552.
It is an arithmetic number, because the mean of its divisors is an integer number (1556615005552).
Almost surely, 23113230011103 is an apocalyptic number.
3113230011103 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113230011103 is an equidigital number, since it uses as much as digits as its factorization.
3113230011103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 3113230011103 its reverse (3011100323113), we get a palindrome (6124330334216).
The spelling of 3113230011103 in words is "three trillion, one hundred thirteen billion, two hundred thirty million, eleven thousand, one hundred three".
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