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31132313130000 = 2435467831811031
BaseRepresentation
bin1110001010000100011100…
…11101110001010000010000
311002020012221102121121102110
413011002032131301100100
513040032434130130000
6150113553123145320
76362143512240645
oct705021635612020
9132205842547373
1031132313130000
119a1315a164965
1235a9798815240
13144a9c28a0b94
14798b52187dcc
1538ec524ba850
hex1c508e771410

31132313130000 has 800 divisors, whose sum is σ = 103899152028672. Its totient is φ = 8027078400000.

The previous prime is 31132313129993. The next prime is 31132313130047. The reversal of 31132313130000 is 3131323113.

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 30196229485 + ... + 30196230515.

Almost surely, 231132313130000 is an apocalyptic number.

31132313130000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31132313130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (51949576014336).

31132313130000 is an abundant number, since it is smaller than the sum of its proper divisors (72766838898672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31132313130000 is a wasteful number, since it uses less digits than its factorization.

31132313130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1393 (or 1372 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 31132313130000 its reverse (3131323113), we get a palindrome (31135444453113).

The spelling of 31132313130000 in words is "thirty-one trillion, one hundred thirty-two billion, three hundred thirteen million, one hundred thirty thousand".