Base | Representation |
---|---|
bin | 1110001010000100011100… |
… | …11101110001010000111111 |
3 | 11002020012221102121121111012 |
4 | 13011002032131301100333 |
5 | 13040032434130130142 |
6 | 150113553123145435 |
7 | 6362143512241043 |
oct | 705021635612077 |
9 | 132205842547435 |
10 | 31132313130047 |
11 | 9a1315a1649a8 |
12 | 35a979881527b |
13 | 144a9c28a0bcc |
14 | 798b52188023 |
15 | 38ec524ba882 |
hex | 1c508e77143f |
31132313130047 has 2 divisors, whose sum is σ = 31132313130048. Its totient is φ = 31132313130046.
The previous prime is 31132313129993. The next prime is 31132313130059. The reversal of 31132313130047 is 74003131323113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31132313130047 - 28 = 31132313129791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31132313129995 and 31132313130022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31132318130047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15566156565023 + 15566156565024.
It is an arithmetic number, because the mean of its divisors is an integer number (15566156565024).
Almost surely, 231132313130047 is an apocalyptic number.
31132313130047 is a deficient number, since it is larger than the sum of its proper divisors (1).
31132313130047 is an equidigital number, since it uses as much as digits as its factorization.
31132313130047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13608, while the sum is 32.
The spelling of 31132313130047 in words is "thirty-one trillion, one hundred thirty-two billion, three hundred thirteen million, one hundred thirty thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •