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3113233313147 is a prime number
BaseRepresentation
bin101101010011011011001…
…010100110110101111011
3102000121210120201120121222
4231103123022212311323
5402001400212010042
610342111042222255
7440631552352346
oct55233312466573
912017716646558
103113233313147
11aa0351052911
1242344765498b
13197765b60649
14aa97769745d
1555eb061a2d2
hex2d4db2a6d7b

3113233313147 has 2 divisors, whose sum is σ = 3113233313148. Its totient is φ = 3113233313146.

The previous prime is 3113233313131. The next prime is 3113233313149. The reversal of 3113233313147 is 7413133323113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3113233313147 - 24 = 3113233313131 is a prime.

Together with 3113233313149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3113233313149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556616656573 + 1556616656574.

It is an arithmetic number, because the mean of its divisors is an integer number (1556616656574).

Almost surely, 23113233313147 is an apocalyptic number.

3113233313147 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113233313147 is an equidigital number, since it uses as much as digits as its factorization.

3113233313147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40824, while the sum is 35.

The spelling of 3113233313147 in words is "three trillion, one hundred thirteen billion, two hundred thirty-three million, three hundred thirteen thousand, one hundred forty-seven".