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311324131 is a prime number
BaseRepresentation
bin10010100011100…
…110110111100011
3210200210220102101
4102203212313203
51114144333011
650520431231
710500132346
oct2243466743
9720726371
10311324131
1114a809478
1288318517
134c664281
142d4c045d
151c4e92c1
hex128e6de3

311324131 has 2 divisors, whose sum is σ = 311324132. Its totient is φ = 311324130.

The previous prime is 311324129. The next prime is 311324141. The reversal of 311324131 is 131423113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311324131 - 21 = 311324129 is a prime.

It is a super-2 number, since 2×3113241312 = 193845429085810322, which contains 22 as substring.

Together with 311324129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 311324099 and 311324108.

It is not a weakly prime, because it can be changed into another prime (311324141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155662065 + 155662066.

It is an arithmetic number, because the mean of its divisors is an integer number (155662066).

Almost surely, 2311324131 is an apocalyptic number.

311324131 is a deficient number, since it is larger than the sum of its proper divisors (1).

311324131 is an equidigital number, since it uses as much as digits as its factorization.

311324131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216, while the sum is 19.

The square root of 311324131 is about 17644.3795867126. The cubic root of 311324131 is about 677.7521878113.

Adding to 311324131 its reverse (131423113), we get a palindrome (442747244).

The spelling of 311324131 in words is "three hundred eleven million, three hundred twenty-four thousand, one hundred thirty-one".