Base | Representation |
---|---|
bin | 1110001010000100101100… |
… | …10101100100111001110111 |
3 | 11002020020021122010110101121 |
4 | 13011002112111210321313 |
5 | 13040033221432344431 |
6 | 150114014202004411 |
7 | 6362150004642442 |
oct | 705022625447167 |
9 | 132206248113347 |
10 | 31132445199991 |
11 | 9a13217770013 |
12 | 35a9814aa6707 |
13 | 144aa140628c5 |
14 | 798b65926659 |
15 | 38ec5dda7611 |
hex | 1c5096564e77 |
31132445199991 has 2 divisors, whose sum is σ = 31132445199992. Its totient is φ = 31132445199990.
The previous prime is 31132445199887. The next prime is 31132445200093. The reversal of 31132445199991 is 19999154423113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31132445199991 - 217 = 31132445068919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31132445599991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15566222599995 + 15566222599996.
It is an arithmetic number, because the mean of its divisors is an integer number (15566222599996).
Almost surely, 231132445199991 is an apocalyptic number.
31132445199991 is a deficient number, since it is larger than the sum of its proper divisors (1).
31132445199991 is an equidigital number, since it uses as much as digits as its factorization.
31132445199991 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9447840, while the sum is 61.
The spelling of 31132445199991 in words is "thirty-one trillion, one hundred thirty-two billion, four hundred forty-five million, one hundred ninety-nine thousand, nine hundred ninety-one".
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