3113304211013 has 2 divisors, whose sum is σ = 3113304211014. Its totient is φ = 3113304211012.

The previous prime is 3113304210983. The next prime is 3113304211037. The reversal of 3113304211013 is 3101124033113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2513673898849 + 599630312164 = 1585457^2 + 774358^2 .

It is an emirp because it is prime and its reverse (3101124033113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3113304211013 - 2¹⁰ = 3113304209989 is a prime.

It is a super-2 number, since 2×3113304211013² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3113304211013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3113304211513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556652105506 + 1556652105507.

It is an arithmetic number, because the mean of its divisors is an integer number (1556652105507).

Almost surely, 2^{3113304211013} is an apocalyptic number.

It is an amenable number.

3113304211013 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113304211013 is an equidigital number, since it uses as much as digits as its factorization.

3113304211013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 3113304211013 its reverse (3101124033113), we get a palindrome (6214428244126).

The spelling of 3113304211013 in words is "three trillion, one hundred thirteen billion, three hundred four million, two hundred eleven thousand, thirteen".