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31133242169 is a prime number
BaseRepresentation
bin11100111111101011…
…111001001100111001
32222100201200120101022
4130333223321030321
51002230102222134
622145153232225
72151340122611
oct347753711471
988321616338
1031133242169
11122269a3707
12604a562675
132c220b46b3
141714b5ba41
15c2337952e
hex73faf9339

31133242169 has 2 divisors, whose sum is σ = 31133242170. Its totient is φ = 31133242168.

The previous prime is 31133242093. The next prime is 31133242171. The reversal of 31133242169 is 96124233113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20531450944 + 10601791225 = 143288^2 + 102965^2 .

It is an emirp because it is prime and its reverse (96124233113) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31133242169 is a prime.

It is a super-2 number, since 2×311332421692 (a number of 22 digits) contains 22 as substring.

Together with 31133242171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (31133242369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15566621084 + 15566621085.

It is an arithmetic number, because the mean of its divisors is an integer number (15566621085).

Almost surely, 231133242169 is an apocalyptic number.

It is an amenable number.

31133242169 is a deficient number, since it is larger than the sum of its proper divisors (1).

31133242169 is an equidigital number, since it uses as much as digits as its factorization.

31133242169 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23328, while the sum is 35.

The spelling of 31133242169 in words is "thirty-one billion, one hundred thirty-three million, two hundred forty-two thousand, one hundred sixty-nine".