311340132013 has 2 divisors, whose sum is σ = 311340132014. Its totient is φ = 311340132012.

The previous prime is 311340131923. The next prime is 311340132053. The reversal of 311340132013 is 310231043113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 217172776324 + 94167355689 = 466018^2 + 306867^2 .

It is a cyclic number.

It is not a de Polignac number, because 311340132013 - 2²⁹ = 310803261101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311340132053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155670066006 + 155670066007.

It is an arithmetic number, because the mean of its divisors is an integer number (155670066007).

Almost surely, 2^311340132013 is an apocalyptic number.

It is an amenable number.

311340132013 is a deficient number, since it is larger than the sum of its proper divisors (1).

311340132013 is an equidigital number, since it uses as much as digits as its factorization.

311340132013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 311340132013 its reverse (310231043113), we get a palindrome (621571175126).

The spelling of 311340132013 in words is "three hundred eleven billion, three hundred forty million, one hundred thirty-two thousand, thirteen".