Base | Representation |
---|---|
bin | 11100111111101110… |
… | …111100100110110111 |
3 | 2222100210012020022002 |
4 | 130333232330212313 |
5 | 1002230303330201 |
6 | 22145222325515 |
7 | 2151346665233 |
oct | 347756744667 |
9 | 88323166262 |
10 | 31134042551 |
11 | 1222739aa87 |
12 | 604a88989b |
13 | 2c22304ab1 |
14 | 1714cc95c3 |
15 | c2348676b |
hex | 73fbbc9b7 |
31134042551 has 2 divisors, whose sum is σ = 31134042552. Its totient is φ = 31134042550.
The previous prime is 31134042497. The next prime is 31134042623. The reversal of 31134042551 is 15524043113.
It is a weak prime.
It is an emirp because it is prime and its reverse (15524043113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31134042551 - 210 = 31134041527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31134042451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15567021275 + 15567021276.
It is an arithmetic number, because the mean of its divisors is an integer number (15567021276).
Almost surely, 231134042551 is an apocalyptic number.
31134042551 is a deficient number, since it is larger than the sum of its proper divisors (1).
31134042551 is an equidigital number, since it uses as much as digits as its factorization.
31134042551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 31134042551 its reverse (15524043113), we get a palindrome (46658085664).
The spelling of 31134042551 in words is "thirty-one billion, one hundred thirty-four million, forty-two thousand, five hundred fifty-one".
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