31134113 has 2 divisors, whose sum is σ = 31134114. Its totient is φ = 31134112.

The previous prime is 31134101. The next prime is 31134127. The reversal of 31134113 is 31143113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18905104 + 12229009 = 4348^2 + 3497^2 .

It is an emirp because it is prime and its reverse (31143113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31134113 - 2⁴ = 31134097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31134091 and 31134100.

It is not a weakly prime, because it can be changed into another prime (31134133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15567056 + 15567057.

It is an arithmetic number, because the mean of its divisors is an integer number (15567057).

Almost surely, 2^31134113 is an apocalyptic number.

It is an amenable number.

31134113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31134113 is an equidigital number, since it uses as much as digits as its factorization.

31134113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108, while the sum is 17.

The square root of 31134113 is about 5579.7950679214. The cubic root of 31134113 is about 314.5904242640.

Adding to 31134113 its reverse (31143113), we get a palindrome (62277226).

The spelling of 31134113 in words is "thirty-one million, one hundred thirty-four thousand, one hundred thirteen".