31143113 has 2 divisors, whose sum is σ = 31143114. Its totient is φ = 31143112.

The previous prime is 31143103. The next prime is 31143157. The reversal of 31143113 is 31134113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18731584 + 12411529 = 4328^2 + 3523^2 .

It is an emirp because it is prime and its reverse (31134113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31143113 - 2⁸ = 31142857 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 31143091 and 31143100.

It is not a weakly prime, because it can be changed into another prime (31143103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571556 + 15571557.

It is an arithmetic number, because the mean of its divisors is an integer number (15571557).

Almost surely, 2^31143113 is an apocalyptic number.

It is an amenable number.

31143113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31143113 is an equidigital number, since it uses as much as digits as its factorization.

31143113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108, while the sum is 17.

The square root of 31143113 is about 5580.6014908789. The cubic root of 31143113 is about 314.6207344369.

Adding to 31143113 its reverse (31134113), we get a palindrome (62277226).

The spelling of 31143113 in words is "thirty-one million, one hundred forty-three thousand, one hundred thirteen".