Base | Representation |
---|---|
bin | 101101010011100111000… |
… | …101010001110110100010 |
3 | 102000122022111221001212220 |
4 | 231103213011101312202 |
5 | 402002302402234132 |
6 | 10342142543331510 |
7 | 440636530625343 |
oct | 55234705216642 |
9 | 12018274831786 |
10 | 3113433243042 |
11 | aa0443998131 |
12 | 4234a25b0b96 |
13 | 1977983c1a65 |
14 | aa99605c0ca |
15 | 55ec2e5da2c |
hex | 2d4e7151da2 |
3113433243042 has 32 divisors (see below), whose sum is σ = 6287625077760. Its totient is φ = 1027685622480.
The previous prime is 3113433243007. The next prime is 3113433243071. The reversal of 3113433243042 is 2403423343113.
It is a happy number.
3113433243042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 3113433242994 and 3113433243012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14016667 + ... + 14237057.
It is an arithmetic number, because the mean of its divisors is an integer number (196488283680).
Almost surely, 23113433243042 is an apocalyptic number.
3113433243042 is an abundant number, since it is smaller than the sum of its proper divisors (3174191834718).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3113433243042 is a wasteful number, since it uses less digits than its factorization.
3113433243042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 243358.
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 3113433243042 its reverse (2403423343113), we get a palindrome (5516856586155).
The spelling of 3113433243042 in words is "three trillion, one hundred thirteen billion, four hundred thirty-three million, two hundred forty-three thousand, forty-two".
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