Base | Representation |
---|---|
bin | 100011011001101111000011… |
… | …1000100001011111000011011 |
3 | 1111211120120112220211011212011 |
4 | 1012303132013010023320123 |
5 | 311303440233122231131 |
6 | 3022143151430530351 |
7 | 122406633141560614 |
oct | 10663360704137033 |
9 | 1454516486734764 |
10 | 311400279883291 |
11 | 90249131895235 |
12 | 2ab135638069b7 |
13 | 1049abc7140701 |
14 | 56c7bd53c8c0b |
15 | 260038129a0b1 |
hex | 11b378710be1b |
311400279883291 has 2 divisors, whose sum is σ = 311400279883292. Its totient is φ = 311400279883290.
The previous prime is 311400279883243. The next prime is 311400279883313. The reversal of 311400279883291 is 192388972004113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311400279883291 - 219 = 311400279359003 is a prime.
It is a super-3 number, since 3×3114002798832913 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (311400279883991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155700139941645 + 155700139941646.
It is an arithmetic number, because the mean of its divisors is an integer number (155700139941646).
Almost surely, 2311400279883291 is an apocalyptic number.
311400279883291 is a deficient number, since it is larger than the sum of its proper divisors (1).
311400279883291 is an equidigital number, since it uses as much as digits as its factorization.
311400279883291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5225472, while the sum is 58.
The spelling of 311400279883291 in words is "three hundred eleven trillion, four hundred billion, two hundred seventy-nine million, eight hundred eighty-three thousand, two hundred ninety-one".
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