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311400279883313 is a prime number
BaseRepresentation
bin100011011001101111000011…
…1000100001011111000110001
31111211120120112220211011212222
41012303132013010023320301
5311303440233122231223
63022143151430530425
7122406633141560645
oct10663360704137061
91454516486734788
10311400279883313
1190249131895255
122ab13563806a15
131049abc714071a
1456c7bd53c8c25
15260038129a0c8
hex11b378710be31

311400279883313 has 2 divisors, whose sum is σ = 311400279883314. Its totient is φ = 311400279883312.

The previous prime is 311400279883291. The next prime is 311400279883349. The reversal of 311400279883313 is 313388972004113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 261538209212449 + 49862070670864 = 16172143^2 + 7061308^2 .

It is a cyclic number.

It is not a de Polignac number, because 311400279883313 - 212 = 311400279879217 is a prime.

It is a super-2 number, since 2×3114002798833132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311400279883393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155700139941656 + 155700139941657.

It is an arithmetic number, because the mean of its divisors is an integer number (155700139941657).

Almost surely, 2311400279883313 is an apocalyptic number.

It is an amenable number.

311400279883313 is a deficient number, since it is larger than the sum of its proper divisors (1).

311400279883313 is an equidigital number, since it uses as much as digits as its factorization.

311400279883313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2612736, while the sum is 53.

The spelling of 311400279883313 in words is "three hundred eleven trillion, four hundred billion, two hundred seventy-nine million, eight hundred eighty-three thousand, three hundred thirteen".