Base | Representation |
---|---|
bin | 101101010100001001000… |
… | …011001001100111000101 |
3 | 102000200210020020022212011 |
4 | 231110021003021213011 |
5 | 402004434244012331 |
6 | 10342315301454221 |
7 | 440656620464134 |
oct | 55241103114705 |
9 | 12020706208764 |
10 | 3114003110341 |
11 | aa0706634942 |
12 | 423621411371 |
13 | 19785949a146 |
14 | aaa0b9dd91b |
15 | 56007ec83b1 |
hex | 2d5090c99c5 |
3114003110341 has 2 divisors, whose sum is σ = 3114003110342. Its totient is φ = 3114003110340.
The previous prime is 3114003110311. The next prime is 3114003110357. The reversal of 3114003110341 is 1430113004113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1650508047841 + 1463495062500 = 1284721^2 + 1209750^2 .
It is a cyclic number.
It is not a de Polignac number, because 3114003110341 - 237 = 2976564156869 is a prime.
It is a super-2 number, since 2×31140031103412 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3114003110311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557001555170 + 1557001555171.
It is an arithmetic number, because the mean of its divisors is an integer number (1557001555171).
Almost surely, 23114003110341 is an apocalyptic number.
It is an amenable number.
3114003110341 is a deficient number, since it is larger than the sum of its proper divisors (1).
3114003110341 is an equidigital number, since it uses as much as digits as its factorization.
3114003110341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3114003110341 its reverse (1430113004113), we get a palindrome (4544116114454).
The spelling of 3114003110341 in words is "three trillion, one hundred fourteen billion, three million, one hundred ten thousand, three hundred forty-one".
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