Base | Representation |
---|---|
bin | 1110001010010010111110… |
… | …11111100001001111101111 |
3 | 11002020222002011012101001021 |
4 | 13011021133133201033233 |
5 | 13040144423414303114 |
6 | 150121323224155011 |
7 | 6362541036056413 |
oct | 705113737411757 |
9 | 132228064171037 |
10 | 31140114994159 |
11 | 9a164a3102986 |
12 | 35ab1b5608a67 |
13 | 144b667060352 |
14 | 7992923d6d43 |
15 | 39005c3c9024 |
hex | 1c525f7e13ef |
31140114994159 has 2 divisors, whose sum is σ = 31140114994160. Its totient is φ = 31140114994158.
The previous prime is 31140114994103. The next prime is 31140114994187. The reversal of 31140114994159 is 95149941104113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31140114994159 - 211 = 31140114992111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31140114995159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15570057497079 + 15570057497080.
It is an arithmetic number, because the mean of its divisors is an integer number (15570057497080).
Almost surely, 231140114994159 is an apocalyptic number.
31140114994159 is a deficient number, since it is larger than the sum of its proper divisors (1).
31140114994159 is an equidigital number, since it uses as much as digits as its factorization.
31140114994159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 699840, while the sum is 52.
The spelling of 31140114994159 in words is "thirty-one trillion, one hundred forty billion, one hundred fourteen million, nine hundred ninety-four thousand, one hundred fifty-nine".
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