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3114021481 is a prime number
BaseRepresentation
bin1011100110011100…
…0011001001101001
322001000120200101221
42321213003021221
522334142141411
61233000142041
7140111513554
oct27147031151
98030520357
103114021481
11135886947a
1272aa67921
133a81c717c
1421780769b
151335b8071
hexb99c3269

3114021481 has 2 divisors, whose sum is σ = 3114021482. Its totient is φ = 3114021480.

The previous prime is 3114021437. The next prime is 3114021527. The reversal of 3114021481 is 1841204113.

3114021481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2842595856 + 271425625 = 53316^2 + 16475^2 .

It is a cyclic number.

It is not a de Polignac number, because 3114021481 - 231 = 966537833 is a prime.

It is a super-2 number, since 2×31140214812 = 19394259568258866722, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3114021881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557010740 + 1557010741.

It is an arithmetic number, because the mean of its divisors is an integer number (1557010741).

Almost surely, 23114021481 is an apocalyptic number.

It is an amenable number.

3114021481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3114021481 is an equidigital number, since it uses as much as digits as its factorization.

3114021481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

The square root of 3114021481 is about 55803.4181838353. The cubic root of 3114021481 is about 1460.2947864447.

Adding to 3114021481 its reverse (1841204113), we get a palindrome (4955225594).

The spelling of 3114021481 in words is "three billion, one hundred fourteen million, twenty-one thousand, four hundred eighty-one".