311413103 has 2 divisors, whose sum is σ = 311413104. Its totient is φ = 311413102.

The previous prime is 311413093. The next prime is 311413153. The reversal of 311413103 is 301314113.

It is a weak prime.

It is an emirp because it is prime and its reverse (301314113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311413103 - 2²² = 307218799 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311413153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155706551 + 155706552.

It is an arithmetic number, because the mean of its divisors is an integer number (155706552).

Almost surely, 2^311413103 is an apocalyptic number.

311413103 is a deficient number, since it is larger than the sum of its proper divisors (1).

311413103 is an equidigital number, since it uses as much as digits as its factorization.

311413103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 311413103 is about 17646.9006627226. The cubic root of 311413103 is about 677.8167456340.

Adding to 311413103 its reverse (301314113), we get a palindrome (612727216).

The spelling of 311413103 in words is "three hundred eleven million, four hundred thirteen thousand, one hundred three".