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311420355461 is a prime number
BaseRepresentation
bin1001000100000100001…
…10011000001110000101
31002202211102100012021022
410202002012120032011
520100242102333321
6355021535000525
731333200226325
oct4420206301605
91082742305238
10311420355461
111100887433a6
1250432069145
132349cb739a7
1411103b95285
15817a0d2dab
hex4882198385

311420355461 has 2 divisors, whose sum is σ = 311420355462. Its totient is φ = 311420355460.

The previous prime is 311420355341. The next prime is 311420355473. The reversal of 311420355461 is 164553024113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 212843822500 + 98576532961 = 461350^2 + 313969^2 .

It is a cyclic number.

It is not a de Polignac number, because 311420355461 - 222 = 311416161157 is a prime.

It is a super-4 number, since 4×3114203554614 (a number of 47 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311420358461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155710177730 + 155710177731.

It is an arithmetic number, because the mean of its divisors is an integer number (155710177731).

Almost surely, 2311420355461 is an apocalyptic number.

It is an amenable number.

311420355461 is a deficient number, since it is larger than the sum of its proper divisors (1).

311420355461 is an equidigital number, since it uses as much as digits as its factorization.

311420355461 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 311420355461 its reverse (164553024113), we get a palindrome (475973379574).

The spelling of 311420355461 in words is "three hundred eleven billion, four hundred twenty million, three hundred fifty-five thousand, four hundred sixty-one".