Base | Representation |
---|---|
bin | 101101010100010110101… |
… | …100101110100100010111 |
3 | 102000201101012010220001002 |
4 | 231110112230232210113 |
5 | 402010421410112211 |
6 | 10342354122053515 |
7 | 440665401125465 |
oct | 55242654564427 |
9 | 12021335126032 |
10 | 3114232113431 |
11 | aa081392729a |
12 | 42368604a29b |
13 | 197894a6a72a |
14 | aaa301b1835 |
15 | 5601d16103b |
hex | 2d516b2e917 |
3114232113431 has 2 divisors, whose sum is σ = 3114232113432. Its totient is φ = 3114232113430.
The previous prime is 3114232113427. The next prime is 3114232113467. The reversal of 3114232113431 is 1343112324113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3114232113431 - 22 = 3114232113427 is a prime.
It is a super-2 number, since 2×31142321134312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3114232113394 and 3114232113403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3114232116431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557116056715 + 1557116056716.
It is an arithmetic number, because the mean of its divisors is an integer number (1557116056716).
Almost surely, 23114232113431 is an apocalyptic number.
3114232113431 is a deficient number, since it is larger than the sum of its proper divisors (1).
3114232113431 is an equidigital number, since it uses as much as digits as its factorization.
3114232113431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 29.
Adding to 3114232113431 its reverse (1343112324113), we get a palindrome (4457344437544).
The spelling of 3114232113431 in words is "three trillion, one hundred fourteen billion, two hundred thirty-two million, one hundred thirteen thousand, four hundred thirty-one".
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