Base | Representation |
---|---|
bin | 11101000000001110… |
… | …100100101001110001 |
3 | 2222101100210102201021 |
4 | 131000032210221301 |
5 | 1002234414124131 |
6 | 22150120135441 |
7 | 2151510314611 |
oct | 350016445161 |
9 | 88340712637 |
10 | 31142333041 |
11 | 12231042826 |
12 | 6051607581 |
13 | 2c23c48501 |
14 | 1716046a41 |
15 | c24072e11 |
hex | 7403a4a71 |
31142333041 has 2 divisors, whose sum is σ = 31142333042. Its totient is φ = 31142333040.
The previous prime is 31142333003. The next prime is 31142333069. The reversal of 31142333041 is 14033324113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27975907600 + 3166425441 = 167260^2 + 56271^2 .
It is an emirp because it is prime and its reverse (14033324113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31142333041 - 217 = 31142201969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31142332997 and 31142333015.
It is not a weakly prime, because it can be changed into another prime (31142330041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571166520 + 15571166521.
It is an arithmetic number, because the mean of its divisors is an integer number (15571166521).
Almost surely, 231142333041 is an apocalyptic number.
It is an amenable number.
31142333041 is a deficient number, since it is larger than the sum of its proper divisors (1).
31142333041 is an equidigital number, since it uses as much as digits as its factorization.
31142333041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 31142333041 its reverse (14033324113), we get a palindrome (45175657154).
The spelling of 31142333041 in words is "thirty-one billion, one hundred forty-two million, three hundred thirty-three thousand, forty-one".
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