Base | Representation |
---|---|
bin | 1110001010011000010110… |
… | …11100111101011000001111 |
3 | 11002021020112012212001200201 |
4 | 13011030023130331120033 |
5 | 13040221331000112421 |
6 | 150122521404034331 |
7 | 6363002400205222 |
oct | 705141334753017 |
9 | 132236465761621 |
10 | 31143000004111 |
11 | 9a17743673626 |
12 | 35ab87b8329a7 |
13 | 144ba06983128 |
14 | 7994876295b9 |
15 | 39017a806b91 |
hex | 1c530b73d60f |
31143000004111 has 2 divisors, whose sum is σ = 31143000004112. Its totient is φ = 31143000004110.
The previous prime is 31143000004063. The next prime is 31143000004187. The reversal of 31143000004111 is 11140000034113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31143000004111 - 241 = 28943976748559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31143000044111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571500002055 + 15571500002056.
It is an arithmetic number, because the mean of its divisors is an integer number (15571500002056).
Almost surely, 231143000004111 is an apocalyptic number.
31143000004111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31143000004111 is an equidigital number, since it uses as much as digits as its factorization.
31143000004111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31143000004111 its reverse (11140000034113), we get a palindrome (42283000038224).
The spelling of 31143000004111 in words is "thirty-one trillion, one hundred forty-three billion, four thousand, one hundred eleven".
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