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311430102311401 is a prime number
BaseRepresentation
bin100011011001111100111100…
…0100111101110000111101001
31111211200102112021222111101121
41012303321320213232013221
5311304432322142431101
63022205003001015241
7122412040154203303
oct10663717047560751
91454612467874347
10311430102311401
119025a845874937
122ab192a7184521
13104a096a7a1b88
1456c942400c973
1526010294ea0a1
hex11b3e789ee1e9

311430102311401 has 2 divisors, whose sum is σ = 311430102311402. Its totient is φ = 311430102311400.

The previous prime is 311430102311387. The next prime is 311430102311407. The reversal of 311430102311401 is 104113201034113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 168500545562176 + 142929556749225 = 12980776^2 + 11955315^2 .

It is an emirp because it is prime and its reverse (104113201034113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311430102311401 - 211 = 311430102309353 is a prime.

It is not a weakly prime, because it can be changed into another prime (311430102311407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715051155700 + 155715051155701.

It is an arithmetic number, because the mean of its divisors is an integer number (155715051155701).

Almost surely, 2311430102311401 is an apocalyptic number.

It is an amenable number.

311430102311401 is a deficient number, since it is larger than the sum of its proper divisors (1).

311430102311401 is an equidigital number, since it uses as much as digits as its factorization.

311430102311401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 311430102311401 its reverse (104113201034113), we get a palindrome (415543303345514).

The spelling of 311430102311401 in words is "three hundred eleven trillion, four hundred thirty billion, one hundred two million, three hundred eleven thousand, four hundred one".