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311431030400047 is a prime number
BaseRepresentation
bin100011011001111101010111…
…1111100000110010000101111
31111211200111220222100021200011
41012303322233330012100233
5311304441222240300142
63022205235033114051
7122412102153630145
oct10663725774062057
91454614828307604
10311431030400047
1190260181741648
122ab19505b58927
13104a0a87b5155c
1456c94b139b595
152601080c24417
hex11b3eaff0642f

311431030400047 has 2 divisors, whose sum is σ = 311431030400048. Its totient is φ = 311431030400046.

The previous prime is 311431030400023. The next prime is 311431030400051. The reversal of 311431030400047 is 740004030134113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 311431030400047 - 235 = 311396670661679 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311431030399991 and 311431030400018.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311431030400057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715515200023 + 155715515200024.

It is an arithmetic number, because the mean of its divisors is an integer number (155715515200024).

Almost surely, 2311431030400047 is an apocalyptic number.

311431030400047 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431030400047 is an equidigital number, since it uses as much as digits as its factorization.

311431030400047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 31.

The spelling of 311431030400047 in words is "three hundred eleven trillion, four hundred thirty-one billion, thirty million, four hundred thousand, forty-seven".