Search a number
-
+
311431030432231 is a prime number
BaseRepresentation
bin100011011001111101010111…
…1111100001110000111100111
31111211200111220222101220211011
41012303322233330032013213
5311304441222242312411
63022205235033523051
7122412102154123033
oct10663725774160747
91454614828356734
10311431030432231
1190260181763846
122ab19505b73487
13104a0a87b630b8
1456c94b13a91c3
152601080c2dc21
hex11b3eaff0e1e7

311431030432231 has 2 divisors, whose sum is σ = 311431030432232. Its totient is φ = 311431030432230.

The previous prime is 311431030432147. The next prime is 311431030432349. The reversal of 311431030432231 is 132234030134113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311431030432231 - 235 = 311396670693863 is a prime.

It is a super-2 number, since 2×3114310304322312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311431030432193 and 311431030432202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311431039432231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715515216115 + 155715515216116.

It is an arithmetic number, because the mean of its divisors is an integer number (155715515216116).

Almost surely, 2311431030432231 is an apocalyptic number.

311431030432231 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431030432231 is an equidigital number, since it uses as much as digits as its factorization.

311431030432231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 311431030432231 its reverse (132234030134113), we get a palindrome (443665060566344).

The spelling of 311431030432231 in words is "three hundred eleven trillion, four hundred thirty-one billion, thirty million, four hundred thirty-two thousand, two hundred thirty-one".