311431324201301 has 2 divisors, whose sum is σ = 311431324201302. Its totient is φ = 311431324201300.

The previous prime is 311431324201247. The next prime is 311431324201397. The reversal of 311431324201301 is 103102423134113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 263118732274225 + 48312591927076 = 16220935^2 + 6950726^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311431324201301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311431324251301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715662100650 + 155715662100651.

It is an arithmetic number, because the mean of its divisors is an integer number (155715662100651).

Almost surely, 2^{311431324201301} is an apocalyptic number.

It is an amenable number.

311431324201301 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431324201301 is an equidigital number, since it uses as much as digits as its factorization.

311431324201301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 311431324201301 its reverse (103102423134113), we get a palindrome (414533747335414).

The spelling of 311431324201301 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred twenty-four million, two hundred one thousand, three hundred one".