Base | Representation |
---|---|
bin | 100011011001111101100000… |
… | …1111110111101101001111010 |
3 | 1111211200112201002000010100021 |
4 | 1012303323001332331221322 |
5 | 311304442332241003424 |
6 | 3022205325050001054 |
7 | 122412112521114154 |
oct | 10663730176755172 |
9 | 1454615632003307 |
10 | 311431333141114 |
11 | 9026031761847a |
12 | 2ab1958b41618a |
13 | 104a0b0579bb94 |
14 | 56c94dd685ad4 |
15 | 260109c5c54e4 |
hex | 11b3ec1fbda7a |
311431333141114 has 4 divisors (see below), whose sum is σ = 467146999711674. Its totient is φ = 155715666570556.
The previous prime is 311431333141063. The next prime is 311431333141121. The reversal of 311431333141114 is 411141333134113.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 311417773703089 + 13559438025 = 17647033^2 + 116445^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 311431333141114.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77857833285277 + ... + 77857833285280.
Almost surely, 2311431333141114 is an apocalyptic number.
311431333141114 is a deficient number, since it is larger than the sum of its proper divisors (155715666570560).
311431333141114 is a wasteful number, since it uses less digits than its factorization.
311431333141114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155715666570559.
The product of its digits is 15552, while the sum is 34.
Adding to 311431333141114 its reverse (411141333134113), we get a palindrome (722572666275227).
The spelling of 311431333141114 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred thirty-three million, one hundred forty-one thousand, one hundred fourteen".
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