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311432030124013 is a prime number
BaseRepresentation
bin100011011001111101110101…
…1100001101111011111101101
31111211200121111122111112010201
41012303323223201233133231
5311310000244202432023
63022205522144433501
7122412136013301241
oct10663735341573755
91454617448445121
10311432030124013
1190260644a96aa7
122ab19744918891
13104a0bb6cc2bb6
1456c9568076421
1526010dd89dbad
hex11b3eeb86f7ed

311432030124013 has 2 divisors, whose sum is σ = 311432030124014. Its totient is φ = 311432030124012.

The previous prime is 311432030123983. The next prime is 311432030124049. The reversal of 311432030124013 is 310421030234113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 166449166704324 + 144982863419689 = 12901518^2 + 12040883^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311432030124013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311432030124613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155716015062006 + 155716015062007.

It is an arithmetic number, because the mean of its divisors is an integer number (155716015062007).

Almost surely, 2311432030124013 is an apocalyptic number.

It is an amenable number.

311432030124013 is a deficient number, since it is larger than the sum of its proper divisors (1).

311432030124013 is an equidigital number, since it uses as much as digits as its factorization.

311432030124013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 311432030124013 its reverse (310421030234113), we get a palindrome (621853060358126).

The spelling of 311432030124013 in words is "three hundred eleven trillion, four hundred thirty-two billion, thirty million, one hundred twenty-four thousand, thirteen".