Base | Representation |
---|---|
bin | 100011011001111101110101… |
… | …1101001010111000101111110 |
3 | 1111211200121111210020222210010 |
4 | 1012303323223221113011332 |
5 | 311310000300210334324 |
6 | 3022205522255324050 |
7 | 122412136036260054 |
oct | 10663735351270576 |
9 | 1454617453228703 |
10 | 311432032121214 |
11 | 90260646130584 |
12 | 2ab19745520626 |
13 | 104a0bb7541c84 |
14 | 56c95684361d4 |
15 | 26010ddb45829 |
hex | 11b3eeba5717e |
311432032121214 has 16 divisors (see below), whose sum is σ = 639698228141328. Its totient is φ = 101004983390592.
The previous prime is 311432032121207. The next prime is 311432032121239. The reversal of 311432032121214 is 412121230234113.
It is a super-2 number, since 2×3114320321212142 (a number of 30 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 701423495547 + ... + 701423495990.
It is an arithmetic number, because the mean of its divisors is an integer number (39981139258833).
Almost surely, 2311432032121214 is an apocalyptic number.
311432032121214 is an abundant number, since it is smaller than the sum of its proper divisors (328266196020114).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311432032121214 is a wasteful number, since it uses less digits than its factorization.
311432032121214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1402846991579.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 311432032121214 its reverse (412121230234113), we get a palindrome (723553262355327).
The spelling of 311432032121214 in words is "three hundred eleven trillion, four hundred thirty-two billion, thirty-two million, one hundred twenty-one thousand, two hundred fourteen".
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