Base | Representation |
---|---|
bin | 1001000100000110100… |
… | …10000101011000011011 |
3 | 1002202212210200110120021 |
4 | 10202003102011120123 |
5 | 20100312142414433 |
6 | 355023524211311 |
7 | 31333531013623 |
oct | 4420322053033 |
9 | 1082783613507 |
10 | 311440201243 |
11 | 110098968876 |
12 | 50438839b37 |
13 | 234a4001b62 |
14 | 1110667d883 |
15 | 817bc0322d |
hex | 488348561b |
311440201243 has 2 divisors, whose sum is σ = 311440201244. Its totient is φ = 311440201242.
The previous prime is 311440201231. The next prime is 311440201283. The reversal of 311440201243 is 342102044113.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311440201243 is a prime.
It is not a weakly prime, because it can be changed into another prime (311440201283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720100621 + 155720100622.
It is an arithmetic number, because the mean of its divisors is an integer number (155720100622).
Almost surely, 2311440201243 is an apocalyptic number.
311440201243 is a deficient number, since it is larger than the sum of its proper divisors (1).
311440201243 is an equidigital number, since it uses as much as digits as its factorization.
311440201243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 311440201243 its reverse (342102044113), we get a palindrome (653542245356).
The spelling of 311440201243 in words is "three hundred eleven billion, four hundred forty million, two hundred one thousand, two hundred forty-three".
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