Base | Representation |
---|---|
bin | 100011011010000010000100… |
… | …1011110000011111000100001 |
3 | 1111211201110222022020111202012 |
4 | 1012310010021132003320201 |
5 | 311310122404314110032 |
6 | 3022214024304002305 |
7 | 122412610226405555 |
oct | 10664041136037041 |
9 | 1454643868214665 |
10 | 311441122410017 |
11 | 90264490390056 |
12 | 2ab1b461900395 |
13 | 104a1a059157a2 |
14 | 56c9b8b831865 |
15 | 2601471c096b2 |
hex | 11b4109783e21 |
311441122410017 has 2 divisors, whose sum is σ = 311441122410018. Its totient is φ = 311441122410016.
The previous prime is 311441122410013. The next prime is 311441122410073. The reversal of 311441122410017 is 710014221144113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 221087428642081 + 90353693767936 = 14869009^2 + 9505456^2 .
It is a cyclic number.
It is not a de Polignac number, because 311441122410017 - 22 = 311441122410013 is a prime.
It is a super-2 number, since 2×3114411224100172 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311441122410013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720561205008 + 155720561205009.
It is an arithmetic number, because the mean of its divisors is an integer number (155720561205009).
Almost surely, 2311441122410017 is an apocalyptic number.
It is an amenable number.
311441122410017 is a deficient number, since it is larger than the sum of its proper divisors (1).
311441122410017 is an equidigital number, since it uses as much as digits as its factorization.
311441122410017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 32.
The spelling of 311441122410017 in words is "three hundred eleven trillion, four hundred forty-one billion, one hundred twenty-two million, four hundred ten thousand, seventeen".
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