Base | Representation |
---|---|
bin | 1110001010011010011110… |
… | …00011000000100100001111 |
3 | 11002021100110020202200002111 |
4 | 13011031033003000210033 |
5 | 13040231141304131421 |
6 | 150123230114404451 |
7 | 6363042450356503 |
oct | 705151703004417 |
9 | 132240406680074 |
10 | 31144134052111 |
11 | 9a18175823683 |
12 | 35abb37590727 |
13 | 144bb578c5452 |
14 | 7995540ac303 |
15 | 3901e5165ee1 |
hex | 1c534f0c090f |
31144134052111 has 2 divisors, whose sum is σ = 31144134052112. Its totient is φ = 31144134052110.
The previous prime is 31144134052093. The next prime is 31144134052121. The reversal of 31144134052111 is 11125043144113.
It is a strong prime.
It is an emirp because it is prime and its reverse (11125043144113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31144134052111 - 27 = 31144134051983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31144134052121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15572067026055 + 15572067026056.
It is an arithmetic number, because the mean of its divisors is an integer number (15572067026056).
Almost surely, 231144134052111 is an apocalyptic number.
31144134052111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31144134052111 is an equidigital number, since it uses as much as digits as its factorization.
31144134052111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 31144134052111 its reverse (11125043144113), we get a palindrome (42269177196224).
The spelling of 31144134052111 in words is "thirty-one trillion, one hundred forty-four billion, one hundred thirty-four million, fifty-two thousand, one hundred eleven".
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