Base | Representation |
---|---|
bin | 11101000000010110… |
… | …100100100101111111 |
3 | 2222101111201222010121 |
4 | 131000112210211333 |
5 | 1002240433224301 |
6 | 22150233115411 |
7 | 2151534200215 |
oct | 350026444577 |
9 | 88344658117 |
10 | 31144429951 |
11 | 12232245208 |
12 | 6052258b67 |
13 | 2c24500a9b |
14 | 1716430cb5 |
15 | c243393a1 |
hex | 7405a497f |
31144429951 has 2 divisors, whose sum is σ = 31144429952. Its totient is φ = 31144429950.
The previous prime is 31144429931. The next prime is 31144430017. The reversal of 31144429951 is 15992444113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31144429951 - 221 = 31142332799 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31144429898 and 31144429907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31144429931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15572214975 + 15572214976.
It is an arithmetic number, because the mean of its divisors is an integer number (15572214976).
Almost surely, 231144429951 is an apocalyptic number.
31144429951 is a deficient number, since it is larger than the sum of its proper divisors (1).
31144429951 is an equidigital number, since it uses as much as digits as its factorization.
31144429951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 43.
The spelling of 31144429951 in words is "thirty-one billion, one hundred forty-four million, four hundred twenty-nine thousand, nine hundred fifty-one".
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